Add Digits
Add Digits math
Given a non-negative integer num, repeatedly add all its digits until the result has only one digit.
For example: Given num = 38, the process is like: 3 + 8 = 11, 1 + 1 = 2. Since 2 has only one digit, return it.
Follow up: Could you do it without any loop/recursion in O(1) runtime?
class AddDigits {
public int addDigits(int num) {
while(num >= 10) {
int temp = 0;
while(num > 0) {
temp += num % 10;
num /= 10;
}
num = temp;
}
return num;
}
}
Last modified October 4, 2020