Word Break

Word Break dynamic programming

Given a non-empty string s and a dictionary wordDict containing a list of non-empty words, determine if s can be segmented into a space-separated sequence of one or more dictionary words. You may assume the dictionary does not contain duplicate words.

For example, given
s = "leetcode",
dict = ["leet", "code"].

Return true because “leetcode” can be segmented as “leet code”.

Word Break Solution

public class WordBreak {
    public boolean wordBreak(String s, Set<String> wordDict) {
        boolean[] dp = new boolean[s.length() + 1];

        dp[0] = true;

        for(int i = 1; i <= s.length(); i++) {
            for(int j = 0; j < i; j++) {
                if(dp[j] && wordDict.contains(s.substring(j, i))) {
                    dp[i] = true;
                    break;
                }
            }
        }

        return dp[s.length()];
    }
}

Last modified October 4, 2020