Merge Intervals
Merge Intervals array
Given a collection of intervals, merge all overlapping intervals.
For example,
Given [1,3],[2,6],[8,10],[15,18]
,
return [1,6],[8,10],[15,18]
.
/**
* Definition for an interval.
* public class Interval {
* int start;
* int end;
* Interval() { start = 0; end = 0; }
* Interval(int s, int e) { start = s; end = e; }
* }
*/
class MergeIntervals {
public List<Interval> merge(List<Interval> intervals) {
List<Interval> result = new ArrayList<Interval>();
if(intervals == null || intervals.size() == 0) {
return result;
}
Interval[] allIntervals = intervals.toArray(new Interval[intervals.size()]);
Arrays.sort(allIntervals, new Comparator<Interval>() {
public int compare(Interval a, Interval b) {
if(a.start == b.start) {
return a.end - b.end;
}
return a.start - b.start;
}
});
for(Interval i: allIntervals) {
if (result.size() == 0 || result.get(result.size() - 1).end < i.start) {
result.add(i);
} else {
result.get(result.size() - 1).end = Math.max(result.get(result.size() - 1).end, i.end);
}
}
return result;
}
}
Last modified October 4, 2020